10x^2+200x-15000=0

Solution for 10x^2+200x-15000=0 equation:

10x^2+200x-15000=0

a = 10; b = 200; c = -15000;
Δ = b2-4ac
Δ = 2002-4·10·(-15000)
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{640000}=800$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-800}{2*10}=\frac{-1000}{20}
=-50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+800}{2*10}=\frac{600}{20}
=30
$